2w^2+9w-2=0

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Solution for 2w^2+9w-2=0 equation: 



2w^2+9w-2=0

a = 2; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·2·(-2)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{97}}{2*2}=\frac{-9-\sqrt{97}}{4}
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{97}}{2*2}=\frac{-9+\sqrt{97}}{4}
$

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